This is a required video lecture 25min for all our second year students. Let us consider a classic relativity scenario. Your friend gets on a rocket ship and blasts off towards Mars at nearly the speed of light. During this journey his clocks tick slower, his lengths contract, and when he arrives to his destination he has aged less than everyone back on Earth. But that's not the only side to this story because from your friend's perspective...
To find the distance at 53°S, we multiply this equatorial distance by the cosine of the latitude. Globe-based result: 66.90 km Flat earth result: 67.01 km Absolute difference: 0.11 km (110 meters) Percentage difference: 0.16% Dr. Alonzo -The Final Experiment: Challenge #3 - SubmissionDownload The use of the cosine function in our formula comes from observational evidence. When we measure the apparent distances between meridians of longitude at...
Sunrise around 5:00am facing 131° SESunset around 10:00pm facing 229° SW17 hours of Daylight Dec 22 edit: There was a typo in section 7, there is a +8 for no reason. TFE-Challenge2-Addment1Download Dr. Alonzo -TFE Challenge #2 - SubmissionDownload Challenge
Flat Earth Lorentz-Latitude Distance Formula The Flat Earth distance formula demonstrates remarkable accuracy across alltest cases provided by Will for this challenge.Maximum error: 28.5 kmMinimum error: 7.6 kmAverage error: 21.35 km Dec 9th Addition 1 was added where we did a short distance calculation. Dec 13th Addition 2 was published where we show why the Firmament has a height of 6371km. Dec 22nd Amendment 2 an adding error was noted when...
Enroll for free FE101: Introduction to Flat FE102: Tracking the PM101: Introduction to Plasma Moon PM201: Mathematics of the Plasma FE200: Celestial Navigation on Flat FE100: Flat Earth Kids Homeschool (8-12)https://students.flatearth.university/courses/fe100 IB200: Global Business Strategies and International Wealth CS101: Introduction to Frontend CS102: Introduction to Backend CS103: Introduction to Android...
Enroll for Free into the Flat Earth University and become empowered with all this knowledge about how the world really works FE101: Introduction to Flat FE102: Tracking the PM101: Introduction to Plasma Moon PM201: Mathematics of the Plasma FE200: Celestial Navigation on Flat FE100: Flat Earth Kids Homeschool (8-12)https://students.flatearth.university/courses/fe100 IB200: Global Business Strategies and International Wealth CS101: Introduction...
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Our recent submission to the MCToon Sextant Challenge has successfully demonstrated a three-star fix algorithm based on Flat Earth geometry, with the final location of latitude 30 and longitude -50 confirming its precision. By using celestial data from an almanac and a brute-force computational approach, the algorithm accurately calculates the observer’s position based solely on the angle of elevation of stars, without requiring spherical...
At the moment it does not seem possible to locate the position at all. At best we could get a lock onto two stars only of the three. However, I am now curious of the final answer so we can verify it is possible. You can read the official challenge information here This is the geometry we need to manipulate Are the angles needed even possible? This is double match location 1 where Dubhe and Arcturus are locked on This is double match location 2...
